MATHS QUETIONS MATHS
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Q17. sum of 3y³+4y²-5y+1 and 3y²-1
= (3y³+4y²-5y+1) + (3y²+1)
= 3y³+4y²-5y+1+3y²+1
= 3y³+7y²-5y+2
sum of 3y³+6y²-y+9 and 4y³+y
= (3y³+6y²-y+9) + (4y³+y)
= 3y³+6y²-y+9+4y³+y
= 7y³+6y²+9
difference between (7y³+6y²+9) - (3y³+7y²-5y+2)
= 7y³+6y²+9-3y³-7y²+5y-2
= 4y³-y²+5y+7
Therefore, 4y³-y²+5y+7 is the difference between them..
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