maths rational number chapter 1 exercise 1A
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Exercise – 1.1
Using appropriate properties find the value of −23×35+52−35×16
Sol. −23×35+52−35×16 – −23×35−35×16+52
=−35(23+16)+52
=−35(4+16)+52
=−35(56)+52
=−1530+52
=−12+52
=42
=2 therefore−23×35+52−35×16 =2
Using appropriate properties find the value of −23×35+52−35×16
Sol. −23×35+52−35×16 – −23×35−35×16+52
=−35(23+16)+52
=−35(4+16)+52
=−35(56)+52
=−1530+52
=−12+52
=42
=2 therefore−23×35+52−35×16 =2
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