Question

Maths SB ch1 pg1.22 Q.156
PLZ explain in detail step by step
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Answer 1

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Answer 2

$\frac{( {2}^{n} + {2}^{n - 1} ) }{( {2}^{n + 1} - {2}^{n} )} \\ = \frac{ \frac{6n}{2} }{2(2n - n)} \\ = \frac{6n}{2} \times \frac{1}{2(2n - n)} \\ = \frac{3n}{2} \times \frac{1}{n} \\ = \frac{3}{2}$

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