Question

maths - secondary school ​

Answer 1

i) consider triangle DCE and triangle LBE

•angle BLE = DCE (alternate angles as DC || BL and DL is a transversal )

• angle BEL = angle CEL (vertically opposite angles)

• CE = EB ( E is a mid point of BC)

by ASA rule

therefore triangle DCE congruent to triangle LBE

ii) BY CPCT

DE = LE

so E is the mid point of BC

Step-by-step explanation:

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