Question

maths
solve
2x^2-3x+5=x^2-5x+13

Answer 1

Answer:

x^2 + 2x-8=0

Step-by-step explanation:

2x^2-3x+5=x^2-5x+13

= 2x^2- x^2-3x+5x+5-13

= x^2+2x-8=0

Or if we find root:-

x^2 +2x -8 =0

= x^2+4x-2x-8=0

= x(x+4) -2x(x+4)

= (x-2) (x+4)

x=2, x= -4

we neglect negative value,

so, x=2