Question

Maths
Solve.....

3(i) (ii)

Answer 1

$HEYA \: \\ \\1) \: \: \: \: \: \: 4 {}^{(x - 2)} = 2 {}^{(x + 1)} \\ \\ 2 {}^{2(x - 2)} = 2 {}^{(x + 1)} \\ \\ now \: compare \: powers \: of \: 2 \: we \: have \: \\ \\ 2(x - 2) = (x + 1) \\ \\ 2x - 4 - x - 1 = 0 \\ \\ x = 5 \\ \\ 2) \: \: \: \\ \\ 3 {}^{x {}^{2} } \times 3 {}^{ - x} = 3 {}^{2} \\ \\ 3 {}^{(x {}^{2 } - x) } = 3 {}^{2} \\ \\ now \: compare \: powers \: of \: 3 \: we \: have \\ \\ (x {}^{2} - x) = 2 \\ \\ x {}^{2} - x - 2 = 0 \\ \\ x {}^{2} - 2x + x - 2 = 0 \\ \\ x(x - 2) + 1(x - 2) = 0 \\ \\ x = 2 \: \: \: or \: \: \: x = - 1$

Answer 2

X equal to 5 dear plz mark me as brilliant