maths
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now take each term and simplify it
i) √48 = √ (2 x 2) × (2 × 2) × 3 = 2 × 2 × √3 = 4√3
ii) √72 = √(3 × 3) (2 × 2) × 2 = 3 × 2 × √2 = 6 √2
iii) √27 = √(3 x 3 ) × 3 = 3√3
iv) 2√18 = 2 √(3 × 3) × 2 = 2 × 3 × √2 = 6 √2
now put these values in given problem
√48-√72-√27 + 2√18
= 4√3-6√2-3√3+6√2
= √3
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