Question

maths
solve the following​

Answer 1

${3x}^{2} - 12x + (n - 5) = 0 \\ = {b}^{2} - 4ac \\ = { - 12}^{2} - 4 \times 3 \times (n - 5) \\ \\ = 144 - 12n + 5 = 0 \\ - 12n = - 144 \\ n = \frac{ - 144}{ - 12} \\ n = 12$

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