Question

maths some one plz help me it would be really nice if you help me ​

Answer 1

Answer:

let angle A be 1x

Angle B be 2x

Angle C be 3x

Angle D be 4x

1+2+3+4= 10

sum of all angles in a quadrilateral=360°

Therefore,

angle a=( 360÷10)*1= 36°

angle b=( 360÷10)*2= 72°

angle c= ( 360÷10)*3= 108°

angle d= ( 360÷10)*4= 144

Answer 2

Answer:

a = 36

b = 72

c = 108

d = 144

Step-by-step explanation:

a: b: c: d

1: 2: 3: 4

when all the 4 angles of a quadrilateral is added it will always be 360 degrees

therefore angles a+ b+ c+ d= 360 degree

a+ b+ c+ d= 360 degree

a + 2a + 3a + 4a = 360 degree

therefore 10a = 360 degree

10 a = 360 degree

so a = 360÷ 10 = 36

therefore

a = 36

b = 36 × 2 = 72

c= 36 × 3 = 108

d = 36 × 4 = 144