Question

maths sum is solve please answeres

Answer 1

$1. \frac{1}{ \sqrt{50} } = \frac{1 \times \sqrt{50} }{ \sqrt{50} \times \sqrt{50} } (multiplying \: both \: numerator \: and \: denominator \: by \: \sqrt{50} ) \\ = \frac{ \sqrt{50} }{50} \\ 2. \frac{5}{3 \sqrt{5} } = \frac{5 \times \sqrt{5} }{3 \sqrt{5} \times \sqrt{5} }(multiplying \: both \: numerator \: and \: denominator \: by \: \sqrt{5} ) \\ = \frac{5 \sqrt{5} }{3 \times 5} = \frac{5 \sqrt{5} }{15} = \frac{ \sqrt{5} }{3} \\ 3. \frac{ \sqrt{75} }{ \sqrt{18}} = \frac{ \sqrt{75} \times \sqrt{18} }{ \sqrt{18} \times \sqrt{18} } (multiplying \: both \: numerator \: and \: denominator \: by \: \sqrt{18} ) \\ = \frac{5 \sqrt{3} \times 3 \sqrt{2} }{18} \\ = \frac{15 \sqrt{6} }{18} \\ = \frac{5 \sqrt{6} }{6} \\ 4. \frac{3 \sqrt{5} }{ \sqrt{6} } = \frac{3 \sqrt{5} \times \sqrt{6} }{ \sqrt{6} \times \sqrt{6} } (multiplying \: both \: numerator \: and \: denominator \: by \: \sqrt{6} ) \\ = \frac{3 \sqrt{30} }{6} \\ = \frac{ \sqrt{30} }{2}$

Answer 2

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