Math, asked by niravrathva3, 6 months ago

maths
125 ^x =  \frac{25}{5 {}^{x} }  \:  \: how \: many \: value \: of \: x

Answers

Answered by EuphoricEpitome
4

Given :

 125 ^x = \dfrac{25}{5^x}

To find :

Value of x

Solution :

25 = 5²

125 = 5 × 5 × 5 = 5³

by putting the exponential values :

 \implies (5^3)^x  = \dfrac{ 5^2}{5^x}

★ Law of exponents -

 \leadsto (a^ m)^n = a^{mn}

\leadsto \frac{a^m}{a^n} = a^{m - n}

by applying the laws -:

\implies 5^{3x} = 5 ^{2 - x}

→ If the base is equal , then the powers also become equal.

3x = 2 - x

3x + x = 2

4x = 2

 \purple{\leadsto x = \frac{1}{2}}

Additional Information :

Laws of exponents -

\implies a^m \times a^n = a^{m+n}

 \implies (a^ m)^n = a^{mn}

\implies \frac{a^m}{a^n} = a^{m - n}

 \implies a^0 = 1

\implies \frac{1}{a^m} = a^{-m}

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