maths trigonometry 10 class
thanweera:
question?
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Answered by
2
Sin A = 1/Cosec A and vice versa
Cos A = 1/Sec A and vice versa
Tan A = 1/Cot A and vice versa
Tan A = Sin A/Cos A
Cot A = Cos A/Sin A
Sin²A + Cos²A = 1
1 + Tan²A = Sec² A
1 + Cot A = Cosec²A
Cos A = 1/Sec A and vice versa
Tan A = 1/Cot A and vice versa
Tan A = Sin A/Cos A
Cot A = Cos A/Sin A
Sin²A + Cos²A = 1
1 + Tan²A = Sec² A
1 + Cot A = Cosec²A
Answered by
2
TanAxCotA=1
tan 30=1/root3
tan45=1
tan60=root3
tan 30=1/root3
tan45=1
tan60=root3
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