Question

mathz lovers
the circled ones​

Answer 1

do multiply of sec theta- tan theta in numerator and denominator.

then change sec theta and tan theta in sin theta and cos theta.

you will get your answer.

Answer 2

HEY MATE!!!
(sinθ - cosθ +1 )/(sinθ +cosθ -1)

dividing numerator and denominator by cosθ

[(sinθ - cosθ +1 )cosθ]/[(sinθ +cosθ -1)/cosθ]
=(tanθ -1 + secθ )/(tanθ +1 - sec θ)
=(tanθ + secθ -1)/(tanθ - sec θ+1)

As, sec²θ- tan²θ = 1
(secθ -tanθ)(secθ +tanθ) = 1

putting this in numerator,
[(tanθ + secθ -(sec²θ- tan²θ)]/(tanθ - sec θ+1)
=[(tanθ + secθ) -(secθ- tanθ)(secθ+tanθ)]/(tanθ - sec θ+1)
=(tanθ+secθ)[1- (secθ - tanθ)]/(tanθ - sec θ+1)
=(tanθ+secθ)[1- secθ + tanθ)]/(tanθ - sec θ+1)
=(tanθ+secθ)

Now, multiplying and dividing by (secθ- tanθ)
[(tanθ+secθ)×(secθ- tanθ)]/(secθ- tanθ)
=(sec²θ- tan²θ)/(secθ- tanθ)
= 1/(secθ- tanθ) 
=RHS
Refer to attachment for more clear answer.....
HOOE IT HELPS YOU!!..