Question

matrix match type:-
column

a) distance - 1) 2 py r

b) displacement - 2) py r

c) circumference of
the circular path - 3) scalar quantity

d) half of the circumference of the circular path - 4) depends on the path followed by the object​

Answer 1

Answer:

a−b+2c=0 ………….(1)

a+2b−c=0 ………….(2)

−3a=3b=3c=1

−122−1a=2−111b=11−12c [From equation (1) and (2), by cross-multiplication method]

1−4a=2+1b=2+1c=1

−3a=1

∴a=−3,b=3,c=3.

a−b+2c=0 ………….(1)

a+2b−c=0 ………….(2)

−3a=3b=3c=1

−122−1a=2−111b=11−12c [From equation (1) and (2), by cross-multiplication method]

1−4a=2+1b=2+1c=1

−3a=1

∴a=−3,b=3,c=3.

a−b+2c=0 ………….(1)

a+2b−c=0 ………….(2)

−3a=3b=3c=1

−122−1a=2−111b=11−12c [From equation (1) and (2), by cross-multiplication method]

1−4a=2+1b=2+1c=1

−3a=1

∴a=−3,b=3,c=3.

a−b+2c=0 ………….(1)

a+2b−c=0 ………….(2)

−3a=3b=3c=1

−122−1a=2−111b=11−12c [From equation (1) and (2), by cross-multiplication method]

1−4a=2+1b=2+1c=1

−3a=1

∴a=−3,b=3,c=3.

a−b+2c=0 ………….(1)

a+2b−c=0 ………….(2)

−3a=3b=3c=1

−122−1a=2−111b=11−12c [From equation (1) and (2), by cross-multiplication method]

1−4a=2+1b=2+1c=1

−3a=1

∴a=−3,b=3,c=3.

a−b+2c=0 ………….(1)

a+2b−c=0 ………….(2)

−3a=3b=3c=1

−122−1a=2−111b=11−12c [From equation (1) and (2), by cross-multiplication method]

1−4a=2+1b=2+1c=1

−3a=1

∴a=−3,b=3,c=3.

a−b+2c=0 ………….(1)

a+2b−c=0 ………….(2)

−3a=3b=3c=1

−122−1a=2−111b=11−12c [From equation (1) and (2), by cross-multiplication method]

1−4a=2+1b=2+1c=1

−3a=1

∴a=−3,b=3,c=3.

Step-by-step explanation:

what do you mean judiciary do you think its devision is partial ir impartial???

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