Question

matter is on the photo

Answer 1

$\sf \green{2. \: \: acceleration \: was \: positive \: when \: it \: was \: coming \: down } \\ \sf \green{ \: \: \: \: \: \: through \: the \: inclied \: plane}$

$\sf \green{ \: \: \: \: acceleration \: was \: zero \: \: when \: it \: was \: moving \: on \: the \:plane.}$

$\sf \green{ \: \: \: \: acceleration \: was \: negative \: when \: it \: was \: movng \: up \: the \: inclined \: plane}$

$\:$

$\sf \red{observation}$

$\:$

$\sf \green{1. \: yes \: there \: was \: change \: in \: the \: speed \: of \: the \: car \: because} \\ \sf \green{ \: \: \: \: \:the \: object \: was \: in \: acceleration \: when \: it \: was \: moving \: down} \\ \sf \green{ \: \: \: \: \: the \: incline \: plane \: and \: in \: decceration \: while \: moving \: up} \\ \sf \green{ \: \: \: \: \: the \: inclined \: plane.}$

$\:$

$\sf \green{3. \: (1) \: \: initial \: velocity \: of \: the \: car \: = 0 \: {ms}^{ - 1} }$

$\sf \green{final \: velocity \: of \: the \: car = 36 \: {km \: h}^{ - 1} }$

$\sf \pink{converting \: 36 {km \: h}^{ - 1} \: into \: {ms}^{ - 1} }$

$\sf \pink{ \implies \: 36 \times \frac{5}{18} }$

$\sf \pink{ \implies \: 5 \times 2}$

$\sf \pink{ \implies \: 10 \: {ms}^{ - 1} }$

$\sf \green{ \therefore \: acceration = \frac{v - u}{t}}$

$\sf \green{ \therefore \: a = \frac{10 - 0}{5}}$

$\sf \green{ \implies \: a = \frac{10 }{5}}$

$\sf \green{ \implies \: a = 2 \: {ms}^{ - 2} }$

$\:$

$\sf \green {3.(2) \: \: v = 10 \: {ms}^{ - 1} }$

$\sf \green{u = 0 \: {ms}^{ - 1}}$

$\sf \green{a = 2 \: {ms}^{ - 2} }$

$\sf \pink{by \: using \: 2nd \: equation \: of \: motion \implies s = ut + { \frac{1}{2}at }^{2} }$

$\sf \pink { \implies s = { \frac{1}{2} \times 2 \times 5}^{2} }$

$\sf \pink { \implies s = { 5}^{2} }$

$\sf \pink { \implies s = 25 \: m}$

$\large \purple{ \mathfrak{hope \: it \: helps \: you}}$