Question

Max electrons with n+l=7

Answer 1

Answer:

Hey there!

Given,

n + l = 7

where,

l = angular momentum quantum number

n = Principle quantum number

From Energy level of electrons we know,

l ≤ n - 1

Satisfying this condition,

The values of n and l will be 7 + 0 ⇒ 7s

6 + 1 ⇒ 6p

5 + 2 ⇒ 5d

4 + 3 ⇒ 4f.

Now:

Case I:

n = 7

l = 0

so, here these represents 7s subshell.

Hence, maximum no. of eletrons will be 2

similarly for n=6,5,4

We got l=1,2,3

whose subshells are 6p,5d,4f

in 6p there are 6 electrons

in 5d there are 10 electrons

in 4f there are 14 electrons

Total no. of electrons = 2+6+10+14= 32 electrons

Hope It Helps You!