max marks =225 obtained marks =173.5 find the percentage
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Step-by-step explanation:

Application of Percentage

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Sumit obtained 225 marks out of 350 and Sunny obtained 240 marks out of 380 in a test. Whose performance is better in the test?

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Hint: The percentage of marks in a test is obtained as given marks divided by the total marks and then multiply the result with 100. From this calculation their percentages and after calculating the person with the highest percentage is the better performer in the test.
Complete step-by-step solution:
From the problem, it is given that,
Marks got by Sumit in a test = 225
Total marks for the Sumit’s test =350
Marks got by Sunny in a test = 240
Total marks for the Sunny’s test = 380
Now to know the best performer in the test we have to calculate their percentages.
Percentage of Sumit got in test =
(Marks got in the testTotal marks for the test)(Marks got in the testTotal marks for the test)
×100×100
Percentage of Sumit got in test =
(225350
Answer:
To Find percentage =
- Marks obtained ×100/ Total marks
STEPS :
173.5×100/225 =
77.11112% ~ 78%
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