Question

maximize Z=45x+80y

subject to 5x+20y≤400
10x+15y≤450
x≥0 , y≥0​

Answer 1

Answer:

12

Step-by-step explanation:

please mark it as brain cells

Answer 2

Given: 5x+20y≤400, 10x+15y≤450, x≥0 , y≥0​

To find:  maximize Z=45x+80y

Solution:

We will first have to find out the coordinates of x and y in the equation 5x+20y≤400 and the coordinates of x and y in the equation 0x+15y≤450.

We get them as (0,20) and (80,0) for first and (0,30) and (45,0) for the other.

We have to plot these points and then find out the enclosed area on the graph. The points of the enclosed area will be (0,20), (0,0), (45,0) and ( 24,14)

Now we will have to find out which points give the maximum value for           Z= 45x+80y.

We put the points of the enclosed figure in the Z equation to find out. After checking for all points, (24,15) give the maximum value.

Z= 45 INTO 24+ 15 INTO 80= 2280

The maximum value for Z=45x+80y is 2280.