Question

Maximum and minimum values of function (x³-3x²-9)

Answer 1

Answer:

Step-by-step explanation:

find fx and put fx=0 and find fxx check whether fxx>0 or fxx<0

if fxx<0 then at x=a the value of function is maximum

fxx>0 then at x=a the value of function is minimum

lets find fx

fx=3x^2-6x

put fx=0

fx=0

3x^2-6x=0

x=2

place x=2 in fxx

fxx=6x-6

fxx(2)=6

here you can see fxx>0

means at x=2 the value of function is minimum

put x=2 in function x^3-3x^2-9

f(2)=-15

minimum value =-15

maximum value= not defined