Maximum area of a triangle with fixed perimeter
Answers
I tried with that formula, but I have problems to solve it. T=s(s−a)(s−b)(s−c)−−−−−−−−−−−−−−−−−√T=s(s−a)(s−b)(s−c) and s=a+b+c2=2d2=ds=a+b+c2=2d2=d and c=2d−a−bc=2d−a−b, I got that T=d(d−a)(d−b)(a+b−d)−−−−−−−−−−−−−−−−−−−−√T=d(d−a)(d−b)(a+b−d). At the end, I got that T2=−d4+(a+b)2d3−(a2+3ab+b2)d2+(a2b+a .
hope you like this answer
please mark me as BRAINLIEST and give a thanks and follow me please
Answer:
Explanation:
I tried with that formula, but I have problems to solve it. T=s(s−a)(s−b)(s−c)−−−−−−−−−−−−−−−−−√T=s(s−a)(s−b)(s−c) and s=a+b+c2=2d2=ds=a+b+c2=2d2=d and c=2d−a−bc=2d−a−b, I got that T=d(d−a)(d−b)(a+b−d)−−−−−−−−−−−−−−−−−−−−√T=d(d−a)(d−b)(a+b−d). At the end, I got that T2=−d4+(a+b)2d3−(a2+3ab+b2)d2+(a2b+a .
hope you like this answer