Maximum efficiency of cationic hydrolysis will be shown by
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Maximum Efficiency of cationic hydrolysis will be shown by:1)AL+3 ,2)Ga +3,3)Tl+1 (1)Tl. metal having positive charge and small size will shown the maximum efficiency of hydrolysis reaction.
AL3+ is the smallest one.
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The given question is incomplete . The complete question is -
" Maximum efficiency of cationic hydrolysis will be shown by : (1) Al+3 (2) Ga+3 (3) Tl+1 (1) Tl. "
Solution:
Maximum efficiency of the cationic hydrolysis will be shown by Al+3 . Hence , option (1) is the correct option .
- Efficiency of Cationic hydrolysis depends upon more positive charge and less size .
- Option (1) and (3) has same charge but Al+3 is smaller in size then Ga+3 .
- Thus , Al+3 is the correct answer .
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