Physics, asked by rtalal759, 6 months ago

Maximum height of projectile with maximum range 400 is​

Answers

Answered by Anonymous
2

Answer:

Rmax  =  u²/g= 400m (Forθ=45 p)

Hmax= u²/2g =400/2 = 200m (For θ=90°)

⇒200m

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