Question

Maximum height reached by a projectile is 4 m. The horizontal range is 12 m, velocity of projection is​

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>>Motion in a Plane

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The maximum height reached by the projectile is 4m. The horizontal range is 12m. Velocity of projection in m/s is (g - acceleration due to gravity)

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Correct option is A)

in a projectile projected at angle θ maximum height and range is given by:

H

max

=4=

2g

u

2

sin

2

θ

−(1)

R=12=

g

u

2

sin2θ

−(2)

Dividing equation (2) by equation (1) :

⇒3=

sin

2

θ

sin2θ

×2

2

3

=

sin

2

θ

2sinθcosθ

⇒tanθ=

3

4

⇒sinθ=

5

4

.

Using equation (1);

⇒4=

2g

u

2

×(

5

4

)

2

⇒u

2

=

2

25g

∴u=5

2

g