Question

maximum limiting molar conductivity among the following at 298K is of..na+,k+mg2+,ca2+ ?​

Answer 1

Answer:

The limiting molar conductivities of NaCl, KBr and KCl are 126, 152 and 150 Scm

2

mol

−1

respectively.

The limiting molar conductivity Λ

o

for NaBr is calculated by the following expression.

λ

NaBr

∞

=λ

NaCl

∞

+λ

KBr

∞

−λ

KCl

∞

λ

NaBr

∞

=126+152−150=128 Scm

2

mol

−1