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(a+b+c)² = (-a-b+c)²
x³ + y³ = (x+y)(x²-xy+y²)
(a+b)² + (a-b)²
= (a²+b²+2ab) + (a²+b²-2ab)
= a²+b²+2ab + a²+b²-2ab
⇒ On cancelling 2ab :
= a²+b²+ a²+b²
= 2a² + 2b²
(a+b+c)² = a² + b² + c² + 2(ab+bc+ca)
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Answer:
a + b + c)³ = a³ + b³ + c³ + 3 (a +b) (b + c) (a+ c) Explanation : Let us just start with. (a+b+c)² = a² +b² + c²+2ab+2bc+2ca. =a² +b² + c²+2(ab+bc+ca)
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