maximum no. of atoms are present in
(A)11..2 liters of So2 at STP
(B)22.4 liters of helium
(C)2.0gms of oxygen
(D)11.2 liters of methane at STP
Answers
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Answer:
op. D
Explanation:
11.2 litres of SO2 = 0.5 moles of SO2 = 0.5 x 64 = 32 gm
22.4 litres of He = 1 mole of He = 4 gm
2 gm of O = (1/32) mole of O
11.2 litre of methane = 0.5 mole of methane
no. of atoms = no. of moles x no. of atoms in one
molecule x Avogadro's no.
In this way, you will find that option D is correct.
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