Question

Maximum no. of hydrogen atoms are in:
(A) 16g of CH4(B) 31.2g of C6H4 (C) 34.2g of C12H22011
.(D) 36g of CoH1206​

Answer 1

Answer: The correct answer is Option B.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$    .....(1)

• For Option A:

Given mass of methane = 16 g

Molar mass of methane = 16 g/mol

Putting values in equation 1, we get:

$\text{Moles of methane}=\frac{16g}{16g/mol}=1mol$

1 mole of methane compound is formed by 1 mole of carbon and 4 moles of hydrogen atoms.

According to mole concept:

1 mole of a gas contains $6.022\times 10^{23}$ number of atoms.

So, 1 mole of methane compound will have $4\times 1\times 6.022\times 10^{23}=24.088\times 10^{23}$ number of hydrogen atoms.

Number of hydrogen atoms = $24.088\times 10^{23}$

• For Option B:

Given mass of $C_6H_4$ = 31.2 g

Molar mass of $C_6H_4$ = 76 g/mol

Putting values in equation 1, we get:

$\text{Moles of }C_6H_4=\frac{31.2g}{76g/mol}=0.41mol$

1 mole of $C_6H_4$ compound is formed by 6 moles of carbon and 4 moles of hydrogen atoms.

According to mole concept:

1 mole of a gas contains $6.022\times 10^{23}$ number of atoms.

So, 0.41 mole of $C_6H_4$ compound will have $4\times 0.41\times 6.022\times 10^{23}=9.876\times 10^{23}$ number of hydrogen atoms.

Number of hydrogen atoms = $9.876\times 10^{23}$

• For Option C:

Given mass of $C_{12}H_{22}O_{11}$ = 34.2 g

Molar mass of $C_{12}H_{22}O_{11}$ = 342.3 g/mol

Putting values in equation 1, we get:

$\text{Moles of }C_{12}H_{22}O_{11}=\frac{34.2g}{342.3g/mol}=0.099mol$

1 mole of $C_{12}H_{22}O_{11}$ compound is formed by 12 moles of carbon, 22 moles of hydrogen atoms and 11 moles of oxygen atoms.

According to mole concept:

1 mole of a gas contains $6.022\times 10^{23}$ number of atoms.

So, 0.099 mole of $C_{12}H_{22}O_{11}$ compound will have $22\times 0.099\times 6.022\times 10^{23}=13.116\times 10^{23}$ number of hydrogen atoms.

Number of hydrogen atoms = $13.116\times 10^{23}$

• For Option D:

Given mass of $C_{6}H_{12}O_{6}$ = 36 g

Molar mass of $C_{6}H_{12}O_{6}$ = 180.156 g/mol

Putting values in equation 1, we get:

$\text{Moles of }C_{6}H_{12}O_{6}=\frac{36g}{180.156g/mol}=0.199mol$

1 mole of $C_{6}H_{12}O_{6}$ compound is formed by 6 moles of carbon, 12 moles of hydrogen atoms and 6 moles of oxygen atoms.

According to mole concept:

1 mole of a gas contains $6.022\times 10^{23}$ number of atoms.

So, 0.199 mole of $C_{6}H_{12}O_{6}$ compound will have $12\times 0.199\times 6.022\times 10^{23}=14.38\times 10^{23}$ number of hydrogen atoms.

Number of hydrogen atoms = $14.38\times 10^{23}$

Hence, the correct answer is Option B.

Answer 2

Explanation:

Answer: The correct answer is Option B.

Explanation:

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}Number of moles=

Molar mass

Given mass

.....(1)

For Option A:

Given mass of methane = 16 g

Molar mass of methane = 16 g/mol

Putting values in equation 1, we get:

\text{Moles of methane}=\frac{16g}{16g/mol}=1molMoles of methane=

16g/mol

16g

=1mol

1 mole of methane compound is formed by 1 mole of carbon and 4 moles of hydrogen atoms.

According to mole concept:

1 mole of a gas contains 6.022\times 10^{23}6.022×10

23

number of atoms.

So, 1 mole of methane compound will have 4\times 1\times 6.022\times 10^{23}=24.088\times 10^{23}4×1×6.022×10

23

=24.088×10

23

number of hydrogen atoms.

Number of hydrogen atoms = 24.088\times 10^{23}24.088×10

23

For Option B:

Given mass of C_6H_4C

6

H

4

= 31.2 g

Molar mass of C_6H_4C

6

H

4

= 76 g/mol

Putting values in equation 1, we get:

\text{Moles of }C_6H_4=\frac{31.2g}{76g/mol}=0.41molMoles of C

6

H

4

=

76g/mol

31.2g

=0.41mol

1 mole of C_6H_4C

6

H

4

compound is formed by 6 moles of carbon and 4 moles of hydrogen atoms.

According to mole concept:

1 mole of a gas contains 6.022\times 10^{23}6.022×10

23

number of atoms.

So, 0.41 mole of C_6H_4C

6

H

4

compound will have 4\times 0.41\times 6.022\times 10^{23}=9.876\times 10^{23}4×0.41×6.022×10

23

=9.876×10

23

number of hydrogen atoms.

Number of hydrogen atoms = 9.876\times 10^{23}9.876×10

23

For Option C:

Given mass of C_{12}H_{22}O_{11}C

12

H

22

O

11

= 34.2 g

Molar mass of C_{12}H_{22}O_{11}C

12

H

22

O

11

= 342.3 g/mol

Putting values in equation 1, we get:

\text{Moles of }C_{12}H_{22}O_{11}=\frac{34.2g}{342.3g/mol}=0.099molMoles of C

12

H

22

O

11

=

342.3g/mol

34.2g

=0.099mol

1 mole of C_{12}H_{22}O_{11}C

12

H

22

O

11

compound is formed by 12 moles of carbon, 22 moles of hydrogen atoms and 11 moles of oxygen atoms.

According to mole concept:

1 mole of a gas contains 6.022\times 10^{23}6.022×10

23

number of atoms.

So, 0.099 mole of C_{12}H_{22}O_{11}C

12

H

22

O

11

compound will have 22\times 0.099\times 6.022\times 10^{23}=13.116\times 10^{23}22×0.099×6.022×10

23

=13.116×10

23

number of hydrogen atoms.

Number of hydrogen atoms = 13.116\times 10^{23}13.116×10

23

For Option D:

Given mass of C_{6}H_{12}O_{6}C

6

H

12

O

6

= 36 g

Molar mass of C_{6}H_{12}O_{6}C

6

H

12

O

6

= 180.156 g/mol

Putting values in equation 1, we get:

\text{Moles of }C_{6}H_{12}O_{6}=\frac{36g}{180.156g/mol}=0.199molMoles of C

6

H

12

O

6

=

180.156g/mol

36g

=0.199mol

1 mole of C_{6}H_{12}O_{6}C

6

H

12

O

6

compound is formed by 6 moles of carbon, 12 moles of hydrogen atoms and 6 moles of oxygen atoms.

According to mole concept:

1 mole of a gas contains 6.022\times 10^{23}6.022×10

23

number of atoms.

So, 0.199 mole of C_{6}H_{12}O_{6}C

6

H

12

O

6

compound will have 12\times 0.199\times 6.022\times 10^{23}=14.38\times 10^{23}12×0.199×6.022×10

23

=14.38×10

23

number of hydrogen atoms.

Number of hydrogen atoms = 14.38\times 10^{23}14.38×10

23

Hence, the correct answer is Option B.