Question

Maximum no of points of intersection of the diagonals of convex octagon

Answer 1

Therefore points of intersection of the diagonal made inside the polygon = nC4 = n! / ( n - 4 )! * 4! here n = number of vertices. maximum number of points of intersection of the diagonal inside the nonagon ( n => 9 ) = 9C4 = 9! / 4!

PLZ MARK AS BRAINLIEST