Maximum number of attempts required to open a 3 slot number lock digit between 0 9
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Answered by
3
The digits used to open a slot are
1, 2, 3, 4, 5, 6, 7, 8
Therefore
Each slot can be opened by choosing any one of 8 digits in 8 ways.
Maximum number of attempts required
= Total number of ways required to open 3 slots
= 8 × 8 × 8
= 512
I hope this answer helps you
1, 2, 3, 4, 5, 6, 7, 8
Therefore
Each slot can be opened by choosing any one of 8 digits in 8 ways.
Maximum number of attempts required
= Total number of ways required to open 3 slots
= 8 × 8 × 8
= 512
I hope this answer helps you
Answered by
1
The question does not tell whether we are supposed to include the digits 0 and 9. So, I'll answer keeping both cases in mind, including and excluding 0 and 9.
If 0 and 9 are included, there are 10 possibilities for each digit. So, total number of possible combinations would be 10×10×10 = 1000.
If 0 and 9 are excluded, there are 8 possibilities for each digit. So, total number of possible combinations would be 8×8×8 = 512.
If 0 and 9 are included, there are 10 possibilities for each digit. So, total number of possible combinations would be 10×10×10 = 1000.
If 0 and 9 are excluded, there are 8 possibilities for each digit. So, total number of possible combinations would be 8×8×8 = 512.
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