Maximum number of electrons in a subshell with l = 3 and n = 4
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Answer: 14 electrons are present
Step-by-step explanation:
l =3
No. of electrons =2(2l+1)
= 2(2×3+1)
= 2(6+1)
= 2(7)
= 14
So total no. Of electrons present is 14
Hope this will help you
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