Question

Maximum number of molecules are present in


5.6 L of CO2 at STP


15 g of CO


4 g of H2


20 g of N2O4

Answer 1

Explanation:

1) 5.6L of co2 at stp

at stp p is 1atm t is 273 k

v given 5.6l

pv=nRT

1×5.6=273×0.0821×n

r=0.0821

n=0.25mol of CO2 molecule

2) 15 g CO

no of moles of co molecule =mass/molar mass

=15/28=0.5357mol of CO molecules

3) 4g H2

no of moles =mass/molar

molar mass of H2 is 2g/mol

4g/2g/mol=2mol of H2 molecule

4)20 gN2O4

molar mass of N2O4 is =92 g/mol

no of moles =mss/molar mass

=20g/92g/mol

=0.217mol of N2O4 MOLECULE

NOTE:: 1MOL = 6.02×10^23 WHICH IS AVOGADRO CONSTANT

SO IF YOU WANT YOU CAN MULTIPLY ANSWER WITH AVOGADRO NUMBER

Answer 2

Answer:

4g of H2 has maximum number of molecules

Explanation:

• number of molecules in 5.6 L of CO2 at STP is 0.25moles

• number of molecules in 15 g of CO is 0.5357 moles

• number of molecules in 4g of H2 is 2 moles

• number of molecules in 20g of N2O4 is 0.217 moles