Question

Maximum number of molecules are present in


5.6 L of CO2 at STP


15 g of CO


4 g of H2


20 g of N2O4

Answer 1

Answer:

the maximum molecules are present in 15 L of h2 gas

........hope it will help you..

Answer 2

Answer:

c) 4g of H2

Explanation:

1. molecules of CO2= (5.6/22.4)*Na=0.25Na (Na=Avogardo's no)

2. molecules of CO=(15/28)*Na=0.53*Na;

3. molecules of H2=(4/2)*Na=2*Na;

4. molecules of N204=(20/92)*Na=0.21*Na; (MW OF N204=14*2+16*4=92)

so as you can see max is in H2 =2*Na;

you can also write the whole value of Na and then calculate but it will not bring any changes to the solution as we have Na in every part..