Question

Maximum number of molecules are present in
51 g of NH3
88 g of CO2
16 g of O2
45 g of H20

Answer 1

Answer:

molecules present are

Explanation:

51g of NH3= 3 molecules

88g of CO2= 2 molecules

16g of O2= 2molecules

45g of H2O= 2 molecules

i am not sure about this answer

Answer 2

Given:

Mass of NH₃ = 51 g

Mass of CO₂ = 88 g

Mass of O₂ = 16 g

Mass of H₂O = 45 g

To find:

The sample in which maximum number of molecules are present

Calculation:

Mass of 1 molecule of NH₃ = 17 g

So in 51 g of NH₃ there will be three molecules

Mass of 1 molecule of CO₂ = 44 g

So in 88 g of CO₂ there will be two molecules

Mass of 1 molecule of O₂ = 32 g

So there will be (1/2) molecule of O₂ present in 32 g of O₂

Mass of 1 molecule of H₂O = 18 g

So in 45 g of H₂O there will be 2.5 molecules

From the above calculation, it can be seen that 51 g of NH₃ has 3 molecules which is maximum

Final answer:

Maximum number of molecules are present in 51 g of NH₃ [Option(a)]