Question

maximum number of moles of Hcl formed when 2g dihydrogen and 35.5g dichlorine react together in presence of sunlight is
a)1mol
b)2mol
c)0.1mol
d)0.5mol​

Answer 1

Answer:

2 mole of Hcl

Explanation:

look the photo

Answer 2

Answer:

2 moles

Explanation:

Given :  

2g dihydrogen and 35.5g dichlorine react together in presence of sunlight

Let the reaction form is $H_2+Cl_2$ → 2HCl

Step: 1

Calculating the numbers of moles

Where n is  $\frac{weight }{Molecular weight}$

$n_H_2 = \frac{2}{2} = 1$

$n_cl_2 = \frac{35.5}{35.5} = 1$

By using stoichiometric coefficient

SR of $H_2$ = SR of $Cl_2$ = SR of $HCl$

Step: 2

On further solving we get:

$\frac{n_H_2}{1} = \frac{n_Cl_2}{1} = \frac{n_Hcl}{1} \\\frac{n_H_2}{1} = \frac{n_HCl}{} \\n_Hcl = 2moles$

Hence, 2 moles of HCl formed when 2g dihydrogen and 35.5g dichlorine react together in presence of sunlight.

What will be the molecular weight of a chemical, consisting 2 moles of H2SO4, 3 moles of SO2 and 1 mole of NaOH? (Na=23, O=16, H=1 S=32)

brainly.in/question/34661854

Dry corrosion is also called as

brainly.in/question/19750130

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