Maximum number of moles of oxygen gas that can be obtained by the electrolytic decomposition of 90 g of water will be
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Electrolytic decomposition of 18 g of water gives 0.5 mole of O2.
So 90 g of water will give (0.5/18)×90 = 2.5 moles of O2.
The max. no of moles of oxygen gas is 2.5 moles
So 90 g of water will give (0.5/18)×90 = 2.5 moles of O2.
The max. no of moles of oxygen gas is 2.5 moles
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right answer is 2.5
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