Question

Maximum number of points of intersection of 5 circles and 4 straight lines is equal to​

Answer 1

Answer:

Therefore, the maximum points of intersection of 5 lines and 4 circles are 62.

Answer 2

Step-by-step explanation:

Two circles intersect at two distinct points. Two straight lines intersect points. Then total numbers of points of intersection.

Two straight lines: $\tt{}^4C_2$

Two circles: $\tt{}^5C_2$,

One line and one circle: $\tt{}^4C_1×{}^5C_1$

Total point of intersection

$\color{darkgreen} \[ \begin{array}{l} \tt=\left(1 \times{ }^{4} C_{2}\right)+\left(2 \times{ }^{5} C_{2}\right)+ \left(2 \times{ }^{4} C_{1} \times{ }^{5} C_{1}\right) \\ \\ \tt =6+20+40 \\ \\ \tt=66 \end{array} \]$

Hence, maximum number of points are 66.