Question

Maximum numbers of node of symmetric binary tree with depth 6 is__
a) 6
b) 60
c) 63
d)36​

Answer 1

Answer:

63 = 2^6-1

Explanation:

the maximum number of node of symmetric binary tree with depth n is 2^n-1.

Answer 2

The maximum number of nodes of a symmetric binary tree with a depth of 6 is 63. (Option C)

• A binary tree is stated to be symmetric if its left and proper subtrees are reflected copies of every other.
• The depth of the tree is described as the best degree of each node withinside the binary tree.
• The depth of the binary tree is one extra than the most important integer.
• The maximum number of nodes of a symmetric binary tree with a depth of n = $2^n$-1
• A symmetric binary tree with depth n (n=6) has the maximum number of nodes for n = 6 is $2^6 - 1$, i.e. 64 - 1 = 63.
• As a result, a symmetric binary tree with a depth of 6 can have up to 63 nodes.