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Is it given that the dipole is entirely inside the box?
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Answered by
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Hey Friend,
Here, we are given that a dipole is there, which consists of two charges of 5 micro couloumb magnitude, and opposite sign.
We are also told that there is a box. We need to assume that the entire dipole is inside the closed box. Otherwise you cannot find an exact answer with the details given.
Let us take that the dipole, and hence both of its charges are inside the closed box.
Now, we use the Gauss Law
Gauss Law states that the Electric Flux passing through any closed surface is equal to the charge enclosed by the surface divided by the Absolute Permittivity.
In Mathematical Form:
Here, represents the Flux passing through the Closed Surface.
Now, Let us see what is the charge enclosed by the surface (here, the box).
There are two charges inside the box.
So, Net Charge enclosed is :
Thus, net charge enclosed by the box is zero.
Thus, we can say:
Thus, The Flux through the Box is Zero.
Hope it helps
Purva
Brainly Community
Here, we are given that a dipole is there, which consists of two charges of 5 micro couloumb magnitude, and opposite sign.
We are also told that there is a box. We need to assume that the entire dipole is inside the closed box. Otherwise you cannot find an exact answer with the details given.
Let us take that the dipole, and hence both of its charges are inside the closed box.
Now, we use the Gauss Law
Gauss Law states that the Electric Flux passing through any closed surface is equal to the charge enclosed by the surface divided by the Absolute Permittivity.
In Mathematical Form:
Here, represents the Flux passing through the Closed Surface.
Now, Let us see what is the charge enclosed by the surface (here, the box).
There are two charges inside the box.
So, Net Charge enclosed is :
Thus, net charge enclosed by the box is zero.
Thus, we can say:
Thus, The Flux through the Box is Zero.
Hope it helps
Purva
Brainly Community
Answered by
0
Answer:
Above answer is perfect
Explanation:
Verified by me ;)
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