Physics, asked by jarnailsingh258, 1 year ago

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QGP: Is it given that the dipole is entirely inside the box?
jarnailsingh258: May be bro,not sure for it

Answers

Answered by QGP
1
Hey Friend,


Here, we are given that a dipole is there, which consists of two charges of 5 micro couloumb magnitude, and opposite sign.

We are also told that there is a box. We need to assume that the entire dipole is inside the closed box. Otherwise you cannot find an exact answer with the details given.


Let us take that the dipole, and hence both of its charges are inside the closed box.

Now, we use the Gauss Law


Gauss Law states that the Electric Flux passing through any closed surface is equal to the charge enclosed by the surface divided by the Absolute Permittivity.

In Mathematical Form:

\phi = \frac{q_{in}}{\varepsilon_{\circ}}

Here, \phi represents the Flux passing through the Closed Surface.



Now, Let us see what is the charge enclosed by the surface (here, the box).


There are two charges inside the box. +5 \mu C \, \, and \, \, -5 \mu C

So, Net Charge enclosed is :

q_{in} = +5 + (-5) = 0

Thus, net charge enclosed by the box is zero. 

Thus, we can say:


\phi = \frac{q_{in}}{\varepsilon_{\circ}} \\ \\ \\ \implies \phi = \frac{0}{\varepsilon_{\circ}} \\ \\ \\ \implies \boxed{\phi=0}


Thus, The Flux through the Box is Zero.



Hope it helps
Purva
Brainly Community

jarnailsingh258: Thanks bro
QGP: You are welcome :)
Answered by FrankFelix
0

Answer:

Above answer is perfect

Explanation:

Verified by me ;)

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