Question

Maximum possible electrons in mn for which n+l+m=5 is/are

Answer 1

Answer : The maximum possible electrons in 'Mn' for which n + l + m = 5 are, 4

Explanation :

There are 4 quantum numbers :

• Principle Quantum Numbers : It describes the size of the orbital. It is represented by n. n = 1,2,3,4....
• Azimuthal Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...
• Magnetic Quantum Number : It describes the orientation of the orbitals. It is represented as $m_l$. The value of this quantum number ranges from $(-l\text{ to }+l)$. When l = 2, the value of $m_l$ will be -2, -1, 0, +1, +2.
• Spin Quantum number : It describes the direction of electron spin. This is represented as $m_s$ The value of this is $+\frac{1}{2}$ for upward spin and $-\frac{1}{2}$ for downward spin.

The electronic configuration of manganese (Mn) atom is, $1s^22s^22p^63s^23p^64s^23d^5$

Now we have to calculate the maximum possible electrons in 'Mn' for which n + l + m = 5

n + l + m = 5 this condition is possible only for $3p\text{ and }3d$

For $3p$ :

$n=3$       (Because it is in 3rd shell)

$l=1$         (Because it is in 'p' orbital)

$m_l=+1,0,-1$     (Because l = 1)

This condition is possible for (+1) value of $m_l$ in which the number of electrons will be, 2

For $3d$ :

$n=3$       (Because it is in 3rd shell)

$l=2$         (Because it is in 'p' orbital)

$m_l=+2,+1,0,-1,-2$     (Because l = 2)

This condition is possible for (0) value of $m_l$ in which the number of electrons will be, 2

Maximum possible electrons in 'Mn' for which n + l + m = 5 are, 4

Therefore, the maximum possible electrons in 'Mn' for which n + l + m = 5 are, 4

Answer 2

Answer:

the maximum no of electrons in Mn for which the n+l+m=5

is 4.

Explanation: