Question

Maximum possible electrons which in cl, for n+l+m =2 is​

Answer 1

Correct option is

B

4

The maximum value of (n+l+m) for all the unpaired electrons of chlorine in its second excited state .

Electronic configuration of chlorine atom

1s22s22p63s23p5

First exited state chlorine atom

1s22s22p63s13p6

Second exited state chlorine atom

1s22s22p63s03p64s1

For only one unpaired electron present present in 4s orbital

Value of n =4

Value of l =0

Value of m =0

Therefore , the maximum value of (n+l+m) for all the unpaired electrons if chlorine in its second excited state .

=4+0+0

=4

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Answer 2

The maximum value of (n+l+m) for all the unpaired electrons of chlorine in its second excited state .

Electronic configuration of chlorine atom

1$s^{2}$2$s^{2}$2$p^{6}$3$s^{2}$3$p^{5}$

First exited state chlorine atom  

1$s^{2}$2$s^{2}$2$p^{6}$3$s^{1}$3$p^{6}$

Second exited state chlorine atom

1$s^{2}$2$s^{2}$2$p^{6}$3$s^{0}$3$p^{5}$4$s^{1}$  

For only one unpaired electron present present in 4s orbital

Value of n =4

Value of l =0

Value of m =0

Therefore , the maximum value of (n+l+m) for all the unpaired electrons if chlorine in its second excited state .

=4+0+0

=4