Question

Maximum profit:

A barrels manufacturer can produce up to 300 barrels per day. the profit made from the sale of these barrels can be

modelled by the function P(x) = - 10x2 + 3500x – 6600 where P(x) is the profit in rupees and x is the number of

barrels made and sold.

1) When no barrels are produced what is a profit / loss

a) 22000 b) 66000 c) 11000 d) 33000

2) What is the breakeven point? (zero profit point is called breakeven)

a) 10 barrels b) 30 barrels c) 20) barrels d) 100 barrels

3) What is the profit / loss if 175 barrels are produced

a) profit 266200 b) loss 266200 c) profit 240250 d) loss 240250

4) What is the profit / loss if 400 barrels are produced

a) profit 266200 b) loss 266200 c) profit 342000 d) loss 342000

5) What is the maximum profit which can manufacturer earn?

a) Rs 240250 b) Rs 480500 c) Rs 680250 d) Rs 250240​

Answer 1

Answer:

5.3 cm. Steps of construction: 1. Draw line segment AB = 5.3 cm. 2. ... Draw angles of the measures given below and draw their bisectors. ... ( c) In ∆ PQR, l(PQ) = 6 cm, l(QR) = 3.8 cm, l(PR) = 4.5