Math, asked by lakshmi1600, 14 days ago

Maximum profit: An barrels manufacturer can produce up to 300 barrels

per day. The profit made from the sale of these barrels can be modelled by

the function P(x) =− 10x2 + 3500x – 66000

where P(x) is the profit in rupees and x is the number of barrels made and

sold.

Based on this model answer the following questions:

(i) When no barrels are produce what is a profit loss?

(a) 22000 (b) 66000 (c) 11000 (d) 33000



(ii) What is the break even point ? (Zero profit point is called break even)

(a) 10 barrels (b) 30 barrels (c) 20 barrels (d) 100 barrels



(iii) What is the profit/loss if 175 barrels are produced

(a) Profit 266200 (b) Loss 266200 (c) Profit 240250 (d) Loss 240250



(iv) What is the profit/loss if 400 barrels are produced

(a) Profit 266200 (b) Loss 266200 (c) Profit 342000 (d) Loss 342000



(v) What is the maximum profit which can manufacturer earn?

(a) Rs 240250 (b) Rs 480500 (c) Rs 680250 (d) Rs 240250​​

Answers

Answered by Sayona1234
0

Rs.240250 is our answer

hope i will help

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