Question

maximum range R by a particle projected at an angle in two dimension. a.0 b.30 c.45 d.60​

Answer 1

Answer:

45°

Explanation:

The range is directly proportional to sin(2¢)

¢=theta

R=sin(2×45)

R=sin(90), sin90 = 1 which is maximum value of sin theta, so max value of range.