maximum rule of sin theta
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sin Tita = 1/cosec
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hhhiiiiii tttthhhhis woolly hhhhellllpppp uuu777
Answered by
1
Hey is your answer.
Sin o· = o
sin 30·= 1/2
sin 45·= 1/ under root 2
sin 60·= under root 3/4
sin 90·= 1
If it is helpful to you then mark me as brainliest
Sin o· = o
sin 30·= 1/2
sin 45·= 1/ under root 2
sin 60·= under root 3/4
sin 90·= 1
If it is helpful to you then mark me as brainliest
Gelageet:
Then mark me as brainliest
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