Chemistry, asked by Anonymous, 2 months ago

Maximum soluble is :- (Ksp is given)
(i) CuS (8.5 × 10^-36)
(ii) CdS (3.6 × 10^-28)
(iii) ZnS (1.2 × 10^-28)
(iv) MnS (1.4 × 10^8)
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Answers

Answered by diajain01
45

{\boxed{\underline{\tt{ \orange{Required  \:  \: Answer:-}}}}}

(iv.) MnS (1.5 × 10^8)

✷GIVEN:-

  • Ksp of MnS ,CdS, CuS, ZnS

  • MnS (1.4 × 10^8)

  • ZnS (1.2 × 10^-28)

  • CdS (3.6 × 10^-28)

  • CuS (8.5 × 10^-36)

✷ TO FIND:-

  • Maximum soluble sulphite.

✷ EXPLANATION:-

Let's see the 1st option---

(i) CuS (8.5 × 10^-36)

:  \longrightarrow \: CuS \: ⇌ \: Cu \:  + S

S \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \: 0 \: \:  \:   +  \:  \:   \: 0</p><p>

0 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \: S\: \:  \:   +  \:  \:   \:  S

\leadsto \: \tt{ Ksp =S^2}

:  \longrightarrow \:  {S}^{2}  = 8.5 \times  {10}^{ - 36}

:  \longrightarrow \: S =  \sqrt{8.5 \times  {10}^{ - 36} }

\leadsto \: { \boxed{ \underline{ \tt{ \purple{S = 2.91 \times  {10}^{ - 18} } }}}}

(ii) CdS (3.6 × 10^-28)

 :  \longrightarrow \: CdS \: ⇌ \: Cd \: \:  + S

S \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \: 0 \: \:  \:   +  \:  \:   \: 0

0 \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \: S\: \:  \:   +  \:  \:   \:   S

\leadsto \: \tt{ Ksp =S^2}

:  \longrightarrow \:  {S}^{2}  = 3.6 \times  {10}^{ - 28}

:  \longrightarrow \: S =  \sqrt{3.6 \times  {10}^{ - 28} }

‎ ‎

 \leadsto \: { \boxed{ \underline{ \tt{ \purple{S =1.89 \times  {10}^{ - 14} } }}}}</p><p>

(iii) ZnS (1.2 × 10^-28)

:\longrightarrow ZnS  ⇌ Zn + S

S \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \: 0 \: \:  \:   +  \:  \:   \: 0

0 \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:   \:  \:  \:  \:  \:  \:  \: \: S\: \:  \:   +  \:  \:   \:   S

\leadsto \: \tt{ Ksp =S^2}

:  \longrightarrow \:  {S}^{2}  = 1.2\times  {10}^{ - 28}

‎ ‎

:  \longrightarrow \: S =  \sqrt{1.2 \times  {10}^{ - 28} }

 \leadsto \: { \boxed{ \underline{ \tt{ \purple{S =1.09 \times  {10}^{ -14} } }}}}</p><p>

(iv) MnS (1.4 × 10^8)

 : \longrightarrow MnS ⇌ Mn + S</p><p>S1 \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \: S1 \: \:  \:   +  \:  \:   \: S1

\leadsto \: \tt{ Ksp =S^2}

:  \longrightarrow \:  {S}^{2}  = 1.4\times  {10}^{ - 8}

:  \longrightarrow \: S =  \sqrt{1.4 \times  {10}^{ - 8} }

 \leadsto \: { \boxed{ \underline{ \tt{ \purple{S =1.018 \times  {10}^{ -4} } }}}}</p><p>

According the solubility, MnS has the maximum solubility.

HOPE IT HELPS

Answered by tishaisherebaba632
1

Answer:

Please answer my first 3 asked questions on brainny

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