Question

maximum value for 3 sin theta + 4 cos theta

Answer 1

Answer:

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Answer 2

Given:

$3\sin \theta+4\ cos \theta$

To find:

Maximum value of above expression

Solution:

As we know the general form :

$a\sin \theta+b\cos \theta$

Here, $a=3,b=4$

So, the maximum value would be :

$\sqrt{a^2+b^2}\\\\=\sqrt{3^2+4^2}\\\\=\sqrt{9+16}\\\\=\sqrt{25}\\\\=5$

Hence, the maximum value is 5.