Question

Maximum value of 4x-x^2

Answer 1

Answer:

6 is the right answer

Step-by-step explanation:

To find the max value we need to differentiate the given equation with respect to X and equate it with zero.

So

Diff. with respect to X

We get

d(2–4x-x²)/dx= -4-2x

Equating it with zero

-4-2x=0 we get

X= -2

For max value of given equation put X=-2 in that equation

2 -4(-2)-(-2)² = 6

So max value of given equation is 6 at X=-2