maximum value of 8cosX-15 sinX-2
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Step-by-step explanation:
The summand 15 can be added later.
Let’s ask, more generally, what are the maximum and minimum values of
f(x)=acosx+bsinx
assuming a and b are not both zero. We can see that, setting c=a2+b2−−−−−−√ , we have
(ac)2+(bc)2=1
and therefore there exists a unique angle φ , with 0≤φ<2π such that
cosφ=ac,sinφ=bc
because (a/c,b/c) is a point on the unit circle. Thus we can write
f(x)=c(accosx+bcsinx)=c(cosxcosφ+sinxsinφ)=ccos(x−φ)
Thus the maximum and minimum values are c and −c .
In your case a=8 and b=15 , so
c=64+225−−−−−−−√=17
Thus the maximum and minimum values of
8cosA+15sinA+15
are, respectively, 17+15=32 and −17+15=−2 .
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