Question

maximum value of x square+x+2 by x square+x+1 is k/3,then k is​

Answer 1

Answer:

x^2+x+2/x^2+x+1=k/3

=3(x^2+x+2)=k(x^2+x+1)

=3x^2+3x+6=kx^2+kx+k

=3x^2-kx^2+3x-kx-k=-6

=3^2-k^2+3-k-k=-6

=9-k^2+3-2k=-6

=-k^2-2k= -6-9-3

=k^2+2k-18=0

=

Step-by-step explanation:

Answer 2

Answer:

9

Step-by-step explanation:

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