Question

maximum velocity of a partical performong simle harmonic motion is 6.284cm/s .if the lenghth of its path is 8 cm calculate the period
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Answer 1

Explanation:

Given: path length = 8 cm, amplitude = 8/2 = 4 cm, Vmax = 6.28 cm/s,

To Find: Period = T =?

Solution:

Vmax = wa

.. @= Vmax/a = 6.28/4 = 1.57 rad/s

T = 2л/w = (2 x 3.14)/ 1.57 = 4 s

Ans: Period = 4 s